![Consider the function f(x)={{:(-2sinx,if,xle-(pi)/(2)),(Asinx+B,if,-(pi)/(2 )ltxlt(pi)/(2)),(cosx,if,xge(pi)/(2)):} Which is continuous everywhere. The value of B is Consider the function f(x)={{:(-2sinx,if,xle-(pi)/(2)),(Asinx+B,if,-(pi)/(2 )ltxlt(pi)/(2)),(cosx,if,xge(pi)/(2)):} Which is continuous everywhere. The value of B is](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/59994322_web.png)
Consider the function f(x)={{:(-2sinx,if,xle-(pi)/(2)),(Asinx+B,if,-(pi)/(2 )ltxlt(pi)/(2)),(cosx,if,xge(pi)/(2)):} Which is continuous everywhere. The value of B is
Evaluate the following limit : lim(x→π/2) (√(2 - sin x) - 1)/(π/2 - x)^2 - Sarthaks eConnect | Largest Online Education Community
How to plot a graph for y=2sin (x+pi/3) +1, x E (0,4pi) show full working out for all intercepts - Quora
If sin x = 1/2 and x is between pi/2 and 3pi/2, what is the value of x/2? (The answer key says it is 5pi/12, but I have no clue how to
Evaluate the following limit : lim(x→π/2) (√(2 - sin x) - 1)/(π/2 - x)^2 - Sarthaks eConnect | Largest Online Education Community
![Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com](https://homework.study.com/cimages/multimages/16/fig_52c2250900925405944793.png)
Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com
![दिखाइए की ` (i) cosx +sin x =sqrt(2) cos (x-( pi)/(4)) =sqrt(2) sin (x+ ( pi)/(4)) ` ` (ii) sqrt(3) - YouTube दिखाइए की ` (i) cosx +sin x =sqrt(2) cos (x-( pi)/(4)) =sqrt(2) sin (x+ ( pi)/(4)) ` ` (ii) sqrt(3) - YouTube](https://i.ytimg.com/vi/gR-Vrcs9R9M/maxresdefault.jpg?sqp=-oaymwEmCIAKENAF8quKqQMa8AEB-AH-CYAC0AWKAgwIABABGGUgZShlMA8=&rs=AOn4CLC7CmUvZ9H43ro_F6yGMShfyRP9Vg)
दिखाइए की ` (i) cosx +sin x =sqrt(2) cos (x-( pi)/(4)) =sqrt(2) sin (x+ ( pi)/(4)) ` ` (ii) sqrt(3) - YouTube
![Evaluate the integral and interpret it as the area of a region. \int_0^\frac{\pi}{2} |2 \sin(x) - 2 \cos(2x)| dx | Homework.Study.com Evaluate the integral and interpret it as the area of a region. \int_0^\frac{\pi}{2} |2 \sin(x) - 2 \cos(2x)| dx | Homework.Study.com](https://homework.study.com/cimages/multimages/16/graph3238217903753176271.jpg)
Evaluate the integral and interpret it as the area of a region. \int_0^\frac{\pi}{2} |2 \sin(x) - 2 \cos(2x)| dx | Homework.Study.com
![Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com](https://homework.study.com/cimages/multimages/16/fig_52a4944619864405640501.png)
Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com
![Let f(x)={-2sinx for -pi<=x <=-pi/2 a sin x+ b for - pi/2 < x < pi/2.cos x for pi/2 <= x <= pi if f is continuous on [-pi, pi).then find the Let f(x)={-2sinx for -pi<=x <=-pi/2 a sin x+ b for - pi/2 < x < pi/2.cos x for pi/2 <= x <= pi if f is continuous on [-pi, pi).then find the](https://d10lpgp6xz60nq.cloudfront.net/ss/web/99525.jpg)